Boyer-Moore’s Majority Vote Algorithm
Explanation
The Boyer-Moore’s Majority Vote algorithm finds whether or not a single element is present in more than half the list. It loops through the list twice and uses a counter with a greedy algorithm to find the element. (If no element is more than half, this program will return -1)
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public class BoyerMooreMajorityVote {
int majority_element(int[] lst) {
int current = lst[0];
int currentcount = 1;
for (int i = 0; i < lst.length; i++) {
if (lst[i] == current) {
currentcount++;
}
else {
currentcount--;
if (currentcount == 0) {
current = lst[i];
currentcount++;
}
}
}
int counter = 0;
for (int i = 0; i < lst.length; i++) {
if (lst[i] == current) {
counter++;
}
}
if (counter > lst.length/2) {
return current;
}
else {
// no overwhelming majority
return -1;
}
}
public static void main(String args[]) {
BoyerMooreMajorityVote boyerMooreMajorityVote = new BoyerMooreMajorityVote();
int[] lst = {1, 3, 3, 2, 1, 1, 1};
int[] lst2 = {1, 2, 3, 1, 2, 1, 3};
System.out.println(boyerMooreMajorityVote.majority_element(lst));
System.out.println(boyerMooreMajorityVote.majority_element(lst2));
}
}